Solutions Manual for Electrochemical Engineering, 1e Thomas Fuller (All Chapters) 1 / 4
Chapter 1 Problem 1 1/1 Electrochemical Engineering, Thomas F. Fuller and John N. Harb 1.1 The original "International Ampere" was defined electrochemically as the current required to deposit 1.118 mg of silver per second from a solution of silver nitrate. Using this definition, how does the international ampere compare to the SI version? (Note that the SI version is based on the Ampere force law).
1.118× 10
−3 g Ag s � mol Ag 107.8682 g Ag �
96485.33 C
equivalent �
- equivalent
mol Ag
= 1.00022 A
The international Ampere is slightly larger than the SI one, which is the current required to create a force of 2×10 -7 N for two parallel wires separated by a distance of 1 m.
J=1A I=1A
I 1m - * F=2xKT 7
N 2 / 4
File:problem 1-2.EES2/9/2015 7:50:28 AM Page 1 EES Ver. 9.724: #2355: For use only by students and faculty in Chemical and Biological Engineering Georgia Tech.Chapter 1, problem 2 deposition of Mo from molten salt MW = 95.94 [g/mol] F = 96485 [coulomb/mol] m = 12.85 [g] I = 7 [coulomb/s] t = 3600 [s] m = I · t · MW F · z z=1.95
SOLUTION
Unit Settings: SI C kPa kJ mass deg
F = 96485 [coulomb/mol]I = 7 [coulomb/s] m = 12.85 [g]MW = 95.94 [g/mol] t = 3600 [s]z = 1.95 No unit problems were detected. 3 / 4
File:problem 1-3.EES2/9/2015 7:51:17 AM Page 1 EES Ver. 9.724: #2355: For use only by students and faculty in Chemical and Biological Engineering Georgia Tech.Chapter 1, problem 3 amount of hydrogen needed to run fuel cell F = 96485 [coulomb/mol] Power = 50000 [W] V = 0.7 [V]cell voltage Power = I · V t = 3600 · 3 · 1 [s] MW = 0.002 [kg/mol]molecular weight of hydrogen n = 2 m = I · t · MW F · n
SOLUTION
Unit Settings: SI C kPa kJ mass deg
F = 96485 [coulomb/mol]I = 71429 [coulomb/s] m = 7.995 [kg]MW = 0.002 [kg/mol] n = 2 Power = 50000 [W] t = 10800 [s]V = 0.7 [V] No unit problems were detected.
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