Solutions Manual Fundamentals of Electric Circuits 7 th Edition By Charles Alexander, Matthew Sadiku (All Chapters 1-19, 100% Original Verified, A+ Grade) This is The Only Original and Complete Solutions Manual for 7 th Edition, All Other Files in the Market are Fake/Old/Wrong Edition.
Part 1: End-of-Chapter Problems’ Solutions
Part 2: Answer Practice Problems
Part 3: Problem Solving Workbook 1 / 4
Chapter 1, Solution 1 (a)q = 6.482x10 17 x [-1.602x10 -19 C] = –103.84 mC (b) q = 1. 24x10 18 x [-1.602x10 -19 C] = –198.65 mC (c) q = 2.46x10 19 x [-1.602x10 -19
C] = –3.941 C
(d) q = 1.628x10 20 x [-1.602x10 -19
C] = –26.08 C
Part 1: End-of-Chapter Problems Soutions 2 / 4
Chapter 1, Solution 2
(a) i = dq/dt = 3 mA (b) i = dq/dt = (16t + 4) A (c) i = dq/dt = (-3e -t
- 10e
- nA
-2t
(d) i=dq/dt = 1200 120 cost pA (e) i =dq/dt = − + − e t t t4 8050100050(cos sin) A
- / 4
Chapter 1, Solution 3
(a) C 1)(3t+=+= q(0)i(t)dt q(t) (b) mC 5t)(t 2
+=++=
q(v)dt s)(2tq(t) (c) ( )q(t) 20 cos 10t /6 q(0) (2sin(10 /6) 1) Ct = + + = + +
(d) C 40t) sin 0.12t(0.16cos40e 30t- +−= − +
=+=
t)cos 40-t40sin30(
1600900
e10 q(0)t40sin10eq(t) -30t 30t-
- / 4