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Test Bank for Principles of Chemistry A Molecular Approach 4 th
(Global Edition) By Nivaldo Tro (All Chapters 1-21, 100% Original Verified, A+ Grade) This is the Only Original Test Bank for 4 th Edition, All Other Files in the Market are Fake/Old/Wrong Edition.
All Chapters Arranged Reverse: 21-1 1 / 4
Chapter 21 Radioactivity and Nuclear Chemistry Multiple Choice Questions 1) Identify the scientist(s) that were awarded the Nobel Prize in physics for the discovery of radioactivity in 1903.
- Johannes Geiger, Marie Curie
- Albert Einstein
- Antoine-Henri Becquerel, Marie Curie, Pierre Curie
- Ernest Rutherford, Johannes Geiger
- Galileo Galilei
Answer: C
Diff: 1 Page Ref: 19.2 2) Identify an alpha particle.
- e
- n
- e
- He
- γ
Answer: D
Diff: 3 Page Ref: 19.3 3) Which of the following statements is TRUE?
- Positrons are similar in ionizing power and penetrating power to beta particles.
- A positron is the antiparticle of the electron.
- Beta decay occurs when a neutron changes into a proton while emitting an electron.
- An alpha particle is a helium 2+ ion.
E) All of the above are true.
Answer: E
Diff: 1 Page Ref: 19.3 4) Which of the following statements is TRUE?
- Gamma rays have the lowest ionizing power of any radioactivity.
- Alpha radiation has the highest penetrating power of any radioactivity.
- Beta emitters will do more damage than alpha emitters within the body.
- Beta radiation has the highest ionizing power of any radioactivity.
E) None of the above are true.
Answer: A
Diff: 1 Page Ref: 19.3 1
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5) Write a nuclear equation for the alpha decay of Am.
- Am → He + Np
- Am → He + Bk
- Am → e + Cm
- Am → e + Pu
- Am → n + Am
Answer: A
Diff: 2 Page Ref: 19.3 6) Write a nuclear equation for the alpha decay of Pu.
- Pu → e + Am
- Pu → He + U
- Pu → e + Np
- Pu → n + Pu
- Pu → e + Np
Answer: B
Diff: 2 Page Ref: 19.3 2
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7) Write a nuclear equation for the alpha decay of U.
- U → n + U
- U → e + Np
- U → He + Th
- U → e + Pa
- U → e + Pa
Answer: C
Diff: 2 Page Ref: 19.3 8) Write the nuclear equation for the alpha decay of Th.
- He + Th → U
- n + Th → Th
- Th → e + Ac
- Th → He + Ra
- Th → e + Pa
Answer: D
Diff: 2 Page Ref: 19.3 3 .
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