1
SOLUTION
- mm#
MN=(10
-3 m)(10 6 N)=10 3 N# m=kN# m Ans.
b) Mg>mm=(10
6 g2 >(10 -3 m2=10 9 g>m=Gg>m Ans.
- km>ms=(10
- kN> 1mm2
3 m)> 110 -3 s2=10 6 m>s=Mm>s Ans.
2 =(10 3 N2 >(10 -3 m) 2 =10 9 N>m 2 =GN>m 2 Ans.1–1. Represent each of the following quantities with combinations of units in the correct SI form, using an
appropriate prefix: (a) mm#
MN, (b) Mg>mm, (c) km>ms, (d) kN>(mm) 2 .
Ans:
- kN#
m
b) Gg>m
c) Mm>s
d) GN>m
2
M01_HIBB9290_01_SE_C01_ANS.indd 122/02/17 4:50 PM
(Fluid Mechanics, 2e Russell Hibbeler) (Solution Manaul, For Complete File, Download link at the end of this File) 1 / 2
2
SOLUTION
- 34.86(10
- m=23.6 Gm Ans.
- (348 mm)
6 )4 2 mm=34.86110 6 24 2 110 -3 m2=23.62110 9
3
=3348(10
-3
- m4
3
=42.14(10
-3
- m
3
=42.1110
-3
- m
- 183,700 mN2
3 Ans.
2
=383,700(10
-3
- N4
2
=7.006(10
3
- N
2
=7.01(10
3
- N
2 Ans.1–2. Evaluate each of the following to three significant figur es, and express each answer in SI units using an
appropriate prefix: (a)
34.86(10
6 )4 2 mm, (b) (348 mm) 3 , (c)(83 700 mN) 2 .
Ans:
- 23.6 Gm
- 42.1110
- m
- 7.01(10
- N
- / 2
-3
3
3
2 M01_HIBB9290_01_SE_C01_ANS.indd 222/02/17 4:50 PM