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Operator Certification Practice Exam

Class notes Jan 1, 2026 ★★★★☆ (4.0/5)
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Advanced Industrial Waste Treatment Operator Certification Practice Exam Questions And Correct Answers (Verified Answers) Plus Rationales 2026 Q&A | Instant Download Pdf

(Comprehensive coverage: physical, chemical, and biological treatment

processes, regulations, safety, and operations)

  • Which parameter best indicates the strength of an industrial
  • wastewater in terms of organic content?

  • Suspended solids
  • Chemical oxygen demand (COD)
  • pH
  • Conductivity

Rationale: COD measures the total quantity of oxygen required to

chemically oxidize organic and inorganic matter, indicating organic strength. 1 / 4

  • The primary purpose of equalization tanks in industrial wastewater

treatment is to:

  • Increase BOD removal efficiency
  • Reduce flow and load fluctuations
  • Improve sludge settling
  • Remove heavy metals

Rationale: Equalization stabilizes flow rate and pollutant concentration to

protect downstream processes from shock loads._

3. A jar test is used to determine:

  • Solids retention time
  • Sludge volume index
  • Optimal coagulant dosage
  • Filter press pressure

Rationale: Jar tests simulate coagulation-flocculation conditions to find the

most effective chemical dose and pH._

  • Which metal hydroxide precipitates best at a pH of about 9.5?
  • Iron
  • Nickel
  • Zinc 2 / 4
  • Chromium

Rationale: Zinc hydroxide achieves minimum solubility around pH 9.5,

making precipitation most effective._

5. The activated sludge process primarily removes:

  • Suspended solids
  • Biodegradable organic matter
  • Dissolved minerals
  • Heavy metals

Rationale: The process relies on microorganisms to metabolize organic

pollutants into biomass and CO₂._

  • Which parameter is most critical for controlling an activated sludge
  • system?

  • Influent COD
  • Sludge age (SRT)
  • Temperature
  • DO saturation level

Rationale: Sludge age determines the microbial population balance and

system stability._

  • / 4

7. The term “F/M ratio” refers to:

  • Food-to-microorganism ratio
  • Flow-to-mass ratio
  • Filtration-to-mixing ratio
  • Feed-to-media ratio

Rationale: F/M defines the organic loading relative to microbial mass and

guides process control._

8. The primary cause of filamentous bulking in activated sludge is:

  • Excessive aeration
  • Low F/M ratio and nutrient imbalance
  • High temperature
  • High pH

Rationale: Low substrate availability and nutrient imbalance favor

filamentous bacteria growth, causing poor settling._

  • Which process uses high pressure to remove dissolved salts from
  • wastewater?

  • Ion exchange
  • Electrodialysis
  • Reverse osmosis
  • Ultrafiltration
  • / 4

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Category: Class notes
Added: Jan 1, 2026
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