Wonderlic Test Questions With Answers

Wonderlic Test Questions With Answers

The beleventh bmonth bof bthe byear bis: b

• bJanuary b
• bNovember b
• bOctober b
• bMay b- bcorrect banswers✔✔The bcorrect banswer bis b(B). bThe beleventh bmonth bof

bthe byear bis bNovember.A bshop bowner bbought bsome bshovels bfor b$5,500. bThe bshovels bwere bsold bfor b$7,300, bwith ba bprofit bof b$50 bper ba bshovel. bHow bmany bshovels bwere binvolved? b

• b18 b
• b36 b
• b55 b
• b73 b
• b90 b
• bNone bof bthese b- bcorrect banswers✔✔The bcorrect banswer bis b(B). bThe btotal bprofit

bfrom bthe bsale bis bthe bselling bprice bminus bthe bcost bof bpurchase, bwhich bis b$7300- $5500= b$1800.If bthe btotal bprofit bis b$1800 band beach bshovel baccounts bfor b$50 bprofit, bthe bamount bof bshovels bis b1800/50=36.How bmany bstates bare bthere bin bthe bU.S.A? b

• b20 b
• b30 b
• b40 b
• b50 b
• b60 b- bcorrect banswers✔✔The bcorrect banswer bis b(D). bThe bUSA bhas b50 bstates.

There bare bthree btimes belephants bcompared bto bgiraffes bin bthe bsafari. bIf bthere bis ba btotal bof b88 belephants band bgiraffes, bhow bmany belephants bare bthere bin bthe bsafari?b

• b22 b
• b31 b
• b43 b
• b59 b
• b66 b 1 / 3

• bNone bof bthese b- bcorrect banswers✔✔The bcorrect banswer bis b(E). bIf bthere bare b3

btimes bas bmany belephants bas bthere bare bgiraffes, bgiraffes bcan bbe bdefined bas bX,

band belephants bas b3X, band bbuild bthe bfollowing bequation: b

3X b+ bX b= b88 b 4X b= b88 b X b= b88/4 b X b= b22 b As bstated babove, bX bstands bfor bthe bnumber bof bgiraffes. bThus, bthere bare b22 bgiraffes. bAs bmentioned bin bthe bproblem, bthere bare bthree btimes bas bmany belephants bas bthere bare bgiraffes bin bthe bsafari. bThus, bto bfind bhow bmany belephants bthere bare

bin bthe bsafari, bmultiply bthe bnumber bof bgiraffes bby b3: b

22 b* b3 b= b66 b 66 bis bthe bnumber bof belephants bin bthe bsafari.What bis bthe bnext bnumber bin bthe bseries? b5, b15, b10, b13, b15, b11, b___ b

• b9 b
• b13 b
• b10 b
• b20 b
• b15 b
• bNone bof bthese b- bcorrect banswers✔✔The bcorrect banswer bis b(D). bThis bseries bis

bmade bup bof btwo bseparate bsubseries bthat balternate: b

• bA bseries bof bnumbers b(the bodd bterms) bthat bincrease bby b5 b(5, b10, b15). b
• bA bseries bof bnumbers b(the beven bterms) bthat bdecrease bby b2 b(15, b13, b11)

The bpattern bis: b5, b15, b10, b13, b15, b11, b___ b

As byou bcan bsee, bthe bnumbers bthat bincrease bby b5 bare bbolded, band bthe bnumbers bthat bdecrease bby b2 bare bunderlined. bWe bare bmissing bthe bseventh bnumber bwhich bis ban bodd bterm; btherefore, bit bshould bbe bgreater bthan bthe blast bodd bterm b(the bfifth bnumber) bby b5. b The bfifth bnumber bis b15. bThus, bthe banswer bis b15 b+ b5 b= b20 A bcar btravels bat ba bspeed bof b85 bmiles bper bhour. bHow bfar bwill bit btravel bin b15 bminutes? b

• b9 bmiles b
• b11 bmiles b
• b13.25 bmiles b
• b21.25 bmiles b
• b22.75 bmiles b 2 / 3

• bNone bof bthese b- bcorrect banswers✔✔The bcorrect banswer bis b(D). bAn bhour

bconsists bof b60 bminutes. bA bquarter bof ban bhour bis b15 bminutes bas b15 b* b4 b= b60.bThus, bdivide bthe bdistance btraveled bper bhour bby b4, bwhich bis b85/4=21.25.A bcar bdealership bsells bused bcars bfor b$7,000 band bnew bcars bfor b$16,000. bIf ba btotal bof b17 bcars bwere bsold bfor b$191,000, bhow bmany bof bthe bcars bsold bwere bused? b

• b2 b
• b3 b
• b5 b
• b8 b
• b10 b
• bNone bof bthese b- bcorrect banswers✔✔The bcorrect banswer bis b(F) b- bNone bof bthe

babove. b First bof ball, bin border bto bsimplify bthe bcalculations bwe bcan bdivide ball bthe bnumbers bby ba bcommon bdenominator: b1000, bin bthat bway bwe bcan bget brid bof ball bthose bannoying bzeroes. bNow bwe bdefine bthe bused bcars bas bU b(with ba bprice bof b7 beach) band bthe bnew bcars bas bN b(with ba bprice bof b16 beach) bNow bwe bcan bbuild btwo bequations, bthe bfirst brepresenting bthe btotal bprice band bthe bsecond bthe btotal bamount

bof bcars: b

• b7U+16N=191 b
• bN+U= b17 b

So baccording bto bthe bsecond bequation bN b= b17-U, band bwe bcan bnow bsubstitute bN bin bthe bfirst bequation: b7U+16(17-U)=191 b; b7U+272-16U=191 b; b9U=81 b; bU=9. b9 bused bcars bwere bsold. b Solving bTip: bYou bcould btry bsolving bthis bquestion bby belimination. bFor bstarters, bsince b191 bis ban bodd bnumber band b16 bis ban beven bnumber, bthen bthe bnumber bof bused bcars bmust bbe bodd b(even+odd=odd) b- bwhich bmeans bwe bcan beliminate banswers bA, bD b& bE. bNow bthat bwe bare bleft bonly bwith bB band bC, blet's btry bto bcalculate bit bfor

beach bof bthese boptions: b

• b3*7 b+ b16*(17-3) b= b245, bwhich bmeans bwe bcan beliminate bB bas ban banswer. b
• b5*7 b+ b16*(17-5) b= b227, bwhich bmeans bwe bcan beliminate bC bas ban banswer. b

Therefore, bthe bonly bpossible banswer bis bF b- bnone bof bthe babove.Joey bgot ba b25% braise bto bhis bsalary. bIf bhis boriginal bsalary bwas b$1,200, bhow bmuch bwas bit bafter bthe braise bwas bimplemented? b

• b$1225 b
• b$1500 b
• b$1350 b
• b$1450 b
• b$1800 b
• / 3